1.-A metal ion with a net + 3 charge has five electronsin the3d subshell. Identi

Question

1.-A metal ion with a net + 3 charge has five electronsin the3d subshell. Identify the metal. 2.-Two atoms have the elctron configurations1s22s22p6 and1s22s22p63s1. The firstionization energy of one is 2080 kJ/mol, and that of the other is496 kJ/mol. Match each ionizzation energy with one of the givenelectron configurations. Justify your choice. 3.- Group the species that are isoelectronic: Be2+,F-, Fe2+, N3-, He,S2-,Co3+, Ar. 1.-A metal ion with a net + 3 charge has five electronsin the3d subshell. Identify the metal. 2.-Two atoms have the elctron configurations1s22s22p6 and1s22s22p63s1. The firstionization energy of one is 2080 kJ/mol, and that of the other is496 kJ/mol. Match each ionizzation energy with one of the givenelectron configurations. Justify your choice. 3.- Group the species that are isoelectronic: Be2+,F-, Fe2+, N3-, He,S2-,Co3+, Ar.

Explanation / Answer

1.-A metal ion with a net + 3 charge has five electronsin the3d subshell. Identify the metal. 1s22s22p63s23p64s03d5 At . no . is ( 2 + 2 + 6 +2 + 6+ 0 + 5 ) +charge = 23 + 3 = 26 So, the metal with at. no. 26 is Iron ( Fe ) At . no . is ( 2 + 2 + 6 +2 + 6+ 0 + 5 ) +charge = 23 + 3 = 26 So, the metal with at. no. 26 is Iron ( Fe ) 2.-Two atoms have the elctron configurations1s22s22p6 and1s22s22p63s1. The first ionization energy of one is 2080 J/mol, and that ofthe other is 496 kJ/mol. For  the elctron configurations1s22s22p6 requires moreenergy to remove an electron .Since it is belongs to ZERO group.Allthe orbitals are completly filled.So, the  firstionization energy of one with 2080 J/mol is forconfigurations1s22s22p6    &the other for configurations1s22s22p63s1 3.- Group the species that are isoelectronic: Be2+,F-, Fe2+, N3-, He,S2-,Co3+, Ar. 3.- Group the species that are isoelectronic: Be2+,F-, Fe2+, N3-, He,S2-,Co3+, Ar. Total no. of electrons in Be2+ atomic number- 2 = 4-2 = 2   simillarly                     F-   = 9+1 = 10                                 Fe2+   = 26 - 2 = 24                                   N3-   = 7 + 3 = 10                                   He    = 2                                    S2- = 16 + 2 = 18                                 Co3+ = 27 - 3 = 24                                    Ar    = 18 The iso electronic groupsare (1)  F-&  N3-                                                 (2 ) Fe2+ & Co3+                                             ( 3 ) S2- & Ar.                                             ( 3 ) S2- & Ar.

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