1.- Give the number of protons and electrons in each of thefollowing common ions

Question

1.- Give the number of protons and electrons in each of thefollowing common ions: Na+, Ca2+,Al3+, I-, F-, Br-,Mn2+, C4-, Cu2+, S2-,N3-, K+, Mg2+,Fe3+. 2.- The atomic masses of 6Li and 7Li are6.0151 amu and 7.0160 amu, respectively. Calculate the naturalabundances of these 2 isotopes. The average atomic mass of Li is6.941 amu. 1.- Give the number of protons and electrons in each of thefollowing common ions: Na+, Ca2+,Al3+, I-, F-, Br-,Mn2+, C4-, Cu2+, S2-,N3-, K+, Mg2+,Fe3+. 2.- The atomic masses of 6Li and 7Li are6.0151 amu and 7.0160 amu, respectively. Calculate the naturalabundances of these 2 isotopes. The average atomic mass of Li is6.941 amu.

Explanation / Answer

I will provide the answer in the following format: (Number ofprotons, number of electrons) (1) Na+ : (11, 10) Ca2+ : (20, 18) Al3+ : (13, 10) F- : (9, 10) Br-: (35, 36) Mn2+: (25, 23) C4- :(6, 10) Cu2+: (29, 27) S2- :(16, 18) N3-: (7, 10) K+: (19, 18) Mg2+: (12, 10) Fe3+ :(26, 23) (2) Let the abundance of 6Li be x and 7Li bey x + y = 100 x = 100 - y (6.0151x + 7.016y)/100 = 6.941 6.0151x + 7.016y = 694.1 6.0151(100 - y) + 7.016y = 694.1 601.51 - 6.0151y + 7.016y = 694.1 1.0009y = 92.59 y = 92.5 x = 100 - 92.5 = 7.5 Thus, the abundance of 6Li is 7.5% whiile the abundanceof 7Li is 92.5% Hope this helps!

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.