1.- Give the values of the quantum numbers associated with thefollowing orbitals
ID: 76562 • Letter: 1
Question
1.- Give the values of the quantum numbers associated with thefollowing orbitals: a) 2p, b) 3s, c) 5d 2.- Give the values of the four quantum numbers of an electronin the following orbitals: a) 3s, b) 4p, c) 3d 3.- Why do the 3s, 3p, and 3d orbitals have the sameenergy in a hydrogen atom but different energies in a many-electronatom? 1.- Give the values of the quantum numbers associated with thefollowing orbitals: a) 2p, b) 3s, c) 5d 2.- Give the values of the four quantum numbers of an electronin the following orbitals: a) 3s, b) 4p, c) 3d 3.- Why do the 3s, 3p, and 3d orbitals have the sameenergy in a hydrogen atom but different energies in a many-electronatom?Explanation / Answer
( 1 ) quantum numbers associated with the followingorbitals: l= 0 for s orbital ; l= 1 forp orbital ; l= 2 for dorbital ; l= 3 for f orbital The values of m are ranging from -l to +l including 0a) 2p n = 2 ; l=1 b) 3s n = 3 ; l=0 c) 5d n = 5 ; l=2 ( 2 ) four quantum numbers of an electron in the followingorbitals: a) 3s n = 3 ; l=0 ; m = 0 ;s = + ( 1/2 ) or -( 1/ 2 ) b) 4p n = 4 ; l=1 ; m = -1, 0 ,+1 ; s = +( 1/2 )and -( 1/ 2 ) for each value of m c) 3d n = 3 ; l =2; m = -2 , -1, 0 ,+1,+2 ; s = + ( 1/2 ) and - ( 1/ 2 ) for each value of m ( 3 ) The energy of a electron in the hydrogen atom depends ononly the principal quantum number n. E 1/n2.
For other systems, the p and d electrons are higher in energy,because they are less penetrating (the higher the angular momentumnumber, the greater the number of radial nodes. So those electronswith low angular momenta have internodal maxima; s electrons have ahigher probability to be closer to the nucleus). So s electrons aremore stabilized, because the other electrons (p and d) have agreater probability to be farther away and be shielded.
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