A voltaic cell is constructed that uses the following reaction and operates at 2

Question

A voltaic cell is constructed that uses the following reaction and operates at 298 K. (Ered Ni+2 is -0.277) Zn(s) + Ni2+(aq) Zn2+(aq) + Ni(s) (a) What is the emf of this cell under standard conditions? _____ V (b) What is the emf of this cell when [Ni2+] = 3.36 M and [Zn2+] = 0.124 M? ____ V (c) What is the emf of the cell when [Ni2+] = 0.196 M and [Zn2+] = 0.838 M? _____V

Explanation / Answer

Zn(2+) + 2?e- ==> Zn(s), E° = -0.76v . . . (1) Ni(2+) + 2?e- ==> Ni(s), E° = -0.25v . . . . (2) (2)-(1): Zn(s) + Ni(2+) ==> Zn(2+) + Ni(s), E° = 0.51V a) the emf of this cell under standard conditions is 0.51V b) the emf of this cell when [Ni2+] = 3.16M and [Zn2+] = 0.151M is: E = E° - RT/nF Ln([Zn2+]/[Ni2+]) = 0.51-(8.314*298/(2*96485))*ln(0.151/3.16… = 0.55 (V)

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