1.- What is the % yield for the reactionPCl 3 (g) + Cl 2 (g) -----> PCl 5 (g)if

Question

1.- What is the % yield for the reactionPCl3(g) + Cl2(g) -----> PCl5(g)if 127.0 g of PCl5 are formed when 83.4 g ofCl2 react with excess PCl3?   a) 125% b) 51.9% c) 66.3% d) 31.4% e)43.7% 2.- How many grams of calcium are required to react with 1.55g of water to produce calcium hydroxide and hydrogengas?   a) 1.72 g b) 6.90 g c) 0.862 g d) 0.696 g e) 3.44 g 1.- What is the % yield for the reactionPCl3(g) + Cl2(g) -----> PCl5(g)if 127.0 g of PCl5 are formed when 83.4 g ofCl2 react with excess PCl3?   a) 125% b) 51.9% c) 66.3% d) 31.4% e)43.7% 2.- How many grams of calcium are required to react with 1.55g of water to produce calcium hydroxide and hydrogengas?   a) 1.72 g b) 6.90 g c) 0.862 g d) 0.696 g e) 3.44 g

Explanation / Answer

theoretical yield: 83.4 g Cl2 *(1mol Cl2/71 grams) *(1 molPCl5/1mol Cl2) *( 208.24 g /1molPCl5) = 244.80 grams Percent yield: actual yield/theoretical yield: 127g/244.80g *100% =51.9%, pick b) 2) Ca + 2H2O     Ca(OH)2 + H2 1.55 g H2O *(1mol H2O/18 g) *(1 mol Ca/2 mol H2O) * (40.1 g Ca/1molCa) = 1.72 grams Ca Pick a)

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