I am in desparation... I don\'t understand how to distinguish where the decimal

Question

I am in desparation... I don't understand how to distinguish where the decimal goesin the following equations: calculate the mass, in g, of ea of the following: 2.74x10^23 helium atoms (2.74x10^22H atoms)x(1mol/6.022x10^23atoms)x(4g ofH/1mol) answer if put in the calculator = 1.8g H (the correct answer0.182gH) question #2 8.2x10^21 Uranium atoms (8.2x10^21U atoms)x(1mol/6.022x10^23atoms)x(238gH/1mol) answer given when put in calculator:3.2g (this is the correctanswer as well, however, I don't understand how the decimal wasmoved in one equation and not the other.) I am so confused. Please help..... :( I am in desparation... I don't understand how to distinguish where the decimal goesin the following equations: calculate the mass, in g, of ea of the following: 2.74x10^23 helium atoms (2.74x10^22H atoms)x(1mol/6.022x10^23atoms)x(4g ofH/1mol) answer if put in the calculator = 1.8g H (the correct answer0.182gH) question #2 8.2x10^21 Uranium atoms (8.2x10^21U atoms)x(1mol/6.022x10^23atoms)x(238gH/1mol) answer given when put in calculator:3.2g (this is the correctanswer as well, however, I don't understand how the decimal wasmoved in one equation and not the other.) I am so confused. Please help..... :( (2.74x10^22H atoms)x(1mol/6.022x10^23atoms)x(4g ofH/1mol) answer if put in the calculator = 1.8g H (the correct answer0.182gH) question #2 8.2x10^21 Uranium atoms (8.2x10^21U atoms)x(1mol/6.022x10^23atoms)x(238gH/1mol) answer given when put in calculator:3.2g (this is the correctanswer as well, however, I don't understand how the decimal wasmoved in one equation and not the other.) I am so confused. Please help..... :(

Explanation / Answer

If the question states 10^23, then the answer will be 1.81g. If the question states 10^22, then the answer will be0.181g.
Either way you have correctly set up the solution for theproblem, which is what matters most!

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