There are many possible isomers for PBr2F2 - but one of these isomers is more st

Question

There are many possible isomers for PBr2F2 - but one of these isomers is more stable than the others, draw the most stable isomer, clearly showing the molecular geometry and positions, explain why it is stable. I think this is the more stable isomer, because the electronegativity of the F and Br atoms are balanced symmetrically, and the repulsion of the lone pair electron is the same for both F and Br? i don't know if this is right [V(NH3)5(SCN)]Br has 3 isomers, draw the isomers and state their relationships to one another, please explain you chose that isomer.

Explanation / Answer

instead of basing it on electronegativity you should base it on the formal charge of of the atom, which is (# of valence e-)-(# of lone pair e- + 1/2 bonding e-) a formal charge closer to 0 will give you a more stable isomer the formal charge of P would be (5)- (2 + 8/2)=-2, so there is probably a more stable isomer

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