How many moles of sulfate ions, aluminum ions, and oxygen atoms arepresent in 50

Question

How many moles of sulfate ions, aluminum ions, and oxygen atoms arepresent in 50.0 g aluminum sulfate? sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol

How many moles of sulfate ions, aluminum ions, and oxygen atoms arepresent in 50.0 g aluminum sulfate? sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol
sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol

How many moles of sulfate ions, aluminum ions, and oxygen atoms arepresent in 50.0 g aluminum sulfate? sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol
sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol sulfate ions 1 mol aluminum ions 2 mol oxygen atoms 3 mol

Explanation / Answer

I am not sure why this question is posted twice but anyways:This is how you should approach this question
1mol Al2(SO4)3 contains 2 mol Al3+ ions, 3 mol SO4 2- ions and 12mol O atoms

molar mass Al2(SO4)3 = 2(27) + 3( 32 + 4(16)) = 342 g/mol
mols of Al2(SO4)3 = 51/ ( 342) = 0.149 mol

ratio Al2(SO4)3 : SO4 2- = 1 : 3
therefore 0.149 mol Al2(SO4)3 = 3 * 0.149 mol SO4 2-
=0.447 molSO4 2-

ratio Al2(SO4)3 : Al3+ = 1 : 2
therefore 0.149 mol Al2(SO4)3 = 2 * 0.149 mol Al3+
=.298 mol Al3+

ratio Al2(SO4)3 : O atoms = 1 : 12
therefore 0.149 mol Al2(SO4)3 = 12 * 0.149 mol O
= 1.788 mol O atoms

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.