EDTA is an organic acid. It is widely used in anaylyzing thehardness (i.e. amoun

Question

EDTA is an organic acid. It is widely used in anaylyzing thehardness (i.e. amount of calcium and magnesium ions) of water. Thestructure of EDTA. Each molecule of EDTA can react with fourmolecules of sodium hydroxide (NaOH). Suppose a solution wasprepared by dissolving 2.0000g of EDTA in 25.00ml of distilledwater. Molecular weight of EDTA = 292.126g/mol. You may assume thedensity of the EDTA solution to be 1.000 g/ml.
a) Calculate the molariy of the EDTAsolution. b) Calculate the normality (in context of acid/basereaction) of the EDTA solution. c) Express the concentration in ppm.
Step by step procedure to acquiring answers to thequestions above would be truly appreciated. Thankyou!!
a) Calculate the molariy of the EDTAsolution. b) Calculate the normality (in context of acid/basereaction) of the EDTA solution. c) Express the concentration in ppm.
Step by step procedure to acquiring answers to thequestions above would be truly appreciated. Thankyou!!

Explanation / Answer

       Volume of solution (in L) = 0.025 L    a) Molarity of solution = no. of moles / volume = 0.274M    b) n-factor of EDTA = 4 (since it can react with 4 NaOHmolecules)           Normality of solution = no. of equivalents/ volume = molarity x n-factor = 0.274 x 4 = 1.096 N    c) Mass of water in solution = 25 x 1 = 25 gms          No. of moles of water = 25/18 = 1.389moles       Concentration in ppm = 0.0068 / 1.389 x1000000 ppm = 4895.61 ppm

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