A 10.00 g sample containing an analyte was transferred to a 250-ml volumetric fl

Question

A 10.00 g sample containing an analyte was transferred to a 250-ml volumetric flask and diluted to volume. When a 10.00-ml aliquot of the resulting solution was diluted to 25.00-ml it was found to give a signal of 0.235(arbitrary units). A second 10.00-ml aliquot was spiked with 10.00-ml of a 1.00 ppm standard solution of the analyte and diluted to 25.00-ml. The signal for the spiked sample was found to be 0.502. Calculate the weight percent of analyte in the original sample. Could you provide an explanation for the steps, please?

Explanation / Answer

the signal is proportional to concentration: let x=wt fraction of analyte in the original sample .235/[x*(10/250)*(10*25)]=.502/[x*(10/… solve for x x=0.0022 or 0.22%

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