A 10.0 mL solution of glucose, C 6 H 12 O 6 (180.18 g/mol), with a mass of 10.48

Question

A 10.0 mL solution of glucose, C6H12O6 (180.18 g/mol), with a mass of 10.483 g, is evaporated to dryness. If the solid white residue has a mass of 0.524 g, what is the mass/mass percent concentration and molarity of the sugar solution? 5.00% and 0.277 M 5.24% and 0.277 M 5.00% and 0.582 M 5.00% and 0.291 M 5.24% and 0.291 M A 10.0 mL solution of glucose, C6H12O6 (180.18 g/mol), with a mass of 10.483 g, is evaporated to dryness. If the solid white residue has a mass of 0.524 g, what is the mass/mass percent concentration and molarity of the sugar solution? Answer 5.00% and 0.277 M 5.24% and 0.277 M 5.00% and 0.582 M 5.00% and 0.291 M 5.24% and 0.291 M

Explanation / Answer

Answer is D

(0.524/10.483)*100 = 4.9986 % which is very very close to 5 %

M = (0.524/180.18)*1000/10 = 0.29082 which is very very close to 0.291 M

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