A 10.0- marble slides to the left with a velocity of magnitude 0.400 on the fric

Question

A 10.0- marble slides to the left with a velocity of magnitude 0.400 on the frictionless, horizontal surface of an icy New York sidewalk and has a head-on, elastic collision with a larger 30.0- marble sliding to the right with a velocity of magnitude 0.200 . Let be to the right. (Since the collision is head-on, all the motion is along a line.)

a)Find the magnitude of the velocity of 30.0- marble after the collision.

B)Find the magnitude of the velocity of 10.0- marble after the collision

c)Calculate the change in momentum (that is, the momentum after the collision minus the momentum before the collision) for 30.0- marble.

D)Calculate the change in momentum for 10.0- marble

E)Calculate the change in momentum for 10.0- marble

f)Calculate the change in kinetic energy (that is, the kinetic energy after the collision minus the kinetic energy before the collision) for 30.0- marble.

g)Calculate the change in kinetic energy for 10.0- marble.

Explanation / Answer

here I am solving first two: I am supposing: Va= speed of 10 g marble Now given: Vb = speed of the 30 g intially Vao= -.4m/s Vbo= .2 m/s we will solve final velocity Vaf=[(Ma-Mb)/(Ma+Mb)]Vao + [(2Mb)/(Ma+Mb)]Vbo Putting the values: Vaf= 0.5 m/s Now for b: Vbf=[(2Ma)/(Ma+Mb)]Vao +[(Mb-Ma)/(Ma+Mb)]Vbo Setting the values = -.01 m/s =0.100m/s left Ans Please rate

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