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Two neighboring Caribbean islands harbor iguana populations. One island (island

ID: 73896 • Letter: T

Question

Two neighboring Caribbean islands harbor iguana populations. One island (island A) has a total iguana population of 800, while the other (island B) has a population less than half that size, numbering 250. On island A, the frequency of an allele p is estimated at 0.75, while this same allele is present at a frequency of 0.90 on island B. During a hurricane tracking across the islands, a group of about 100 iguanas get rafted from island A to island B. What is the frequency of allele p on island B after the hurricane?

Explanation / Answer

for island b

P=i/n

.90= i/250

i= 225

aftrer hurricane

.75 = i/100

= 75

total no. of copies on island b = 225 +75 =300

total population =250 +100 =350

using p= i/n

300/350

= .857 or .86

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