For the reaction 2 NO (g) + O2 (g) -> 2 NO2 (g)... ~See Attached Table~ (A)-Find

Question

For the reaction 2 NO (g) + O2 (g) -> 2 NO2 (g)...

~See Attached Table~

(A)-Find the rate law for this reaction.

(B)-Find the value of the rate of the constant with correct units.

(C)-Find the initial rate of reaction in experiment 4.

For the reaction 2 NO (g) + O2 (g) - > 2 NO2 (g)... ~ See Attached Table ~ For the reaction 2 NO (g) + O2 (g) - > 2 NO2 (g) (A)-Find the rate law for this reaction. (B)-Find the value of the rate of the constant with correct units. (C)-Find the initial rate of reaction in experiment 4.

Explanation / Answer

2/1 gives 6.8 x10^-8 / 3.4 x10^-8 =2 2^m =2 , m=1 , hence 1st order with respect to O2 2/3 6.8/1.7 =4 2^n=4 , n= 2 , hence 2nd order with repest to NO A) rate = k [NO]^2 [O2] rate = 3.4 x10^-8 = k x (3.6 x10^-4)^2 (5.2 x10^-3) B)k = 50 M-2 s C)initial rate = 50 x (1.8 x10^-4 )^2 x 5.2 x10^-3 =0.842 x 10^-8 mole/lit sec

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