Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium ch

Question

Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). This equation is balanced as written:
2HCl(aq)+Na2Co3(aq) --- 2NaCl(aq)+H2O(I)+CO2(g)

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1) What volume of 1.25 M HCl in liters is needed to react completely (with nothing left over) with 0.500 L of 0.500 M Na2CO3 ?



2)A 377 mL sample of unknown HCl solution reacts completely with Na2CO3 to form 18.1 g CO2. What was the concentration of the HCl solution ?

Explanation / Answer

1) v = 2*0.5*0.5 / 1.25 = 0.4 L 2) 18.1 g of CO2 = 18.1/44 moles =0.411363636 mol 2*0.411363636 = 0.377*C C = 2.17998747 M

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