Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium ch

Question

Hydrochloric acid (HCl) reacts with sodium carbonate (Na2CO3), forming sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). This equation is balanced as written:

2HCl(aq)+Na2CO3(aq)2NaCl(aq)+H2O(l)+CO2(g)

Part A

What volume of 1.75 M HCl in liters is needed to react completely (with nothing left over) with 0.750 L of 0.100 M Na2CO3?

Express your answer to three significant figures and include the appropriate units.

Part B

A 557-mL sample of unknown HCl solution reacts completely with Na2CO3 to form 20.1 g CO2. What was the concentration of the HClsolution?

Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

A)

ratio is: 2:1

so mol of Na2CO3 = MV = 0.75*0.1 = 0.075 mol of Na2CO3

so we need 2x amount of HCl

0.075 mol --> 0.075*2 = 0.15 mol of HCl

M = mopl/V

V = mol/M

V = 0.15 / 1.75 = 0.085714 Liters of HCL required

B)

V = 557 mL o fHCl is reacted

mol of CO2 = mass/MW = 20.1/44 = 0.45681 mol of CO2

ratio is:

1 mol of CO2 = 1 mol of HCl

0.45681 mol --> 0.45681mol of HCl

M = mol/V

M = 0.45681 / (0.557) = 0.820125Mof HCl

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