1. How many ATOMS of carbon are present in 6.55 grams of carbon tetrafluoride ?

Question

1. How many ATOMS of carbon are present in 6.55 grams of carbon tetrafluoride ? atoms of carbon .

2. How many GRAMS of fluorine are present in 1.02×1023molecules of carbon tetrafluoride ?  grams of fluorine .

3.. How many MOLECULES of sulfur dichloride are present in 8.95 grams of this compound ?   molecules.

4.How many GRAMS of sulfur dichloride are present in 7.99×1022 molecules of this compound ?   grams.

5. How many Ca atoms are there in a 102 gram sample of Ca ?
atoms

6.How many grams of Ge are there in a sample of Ge that contains 6.78×1023atoms? grams

Explanation / Answer

According to chegg rules we have to answer only first one problem

1.

Number of moles = amount in g / molar mass

= 6.55 g / 88.0043 g/mol

=0.0744 mole CF4

1 mole of CF4 contains one mole C

Therefore

0.0744 mole CF4 = 0.0744 mole C

1 mole = 6.022*10^23 atoms

Then;

0.0744 mole C *6.022*10^23 atom s/ 1 mole

= 0.45 *10^23 atoms C

= 4.5*10^22 atom C

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