1. How many ATOMS of carbon are present in 7.09 grams of carbon monxide? _____ a

Question

1. How many ATOMS of carbon are present in 7.09 grams of carbon monxide? _____ atoms of carbon

2.  How many GRAMS of oxygen are present in 4.89×1022 molecules of carbon monoxide ? ______ grams of oxygen

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3. How many ATOMS of phosphorus are present in 7.29 grams of tetraphosphorus decaoxide ? ______ atoms of phosphorus

4. How many GRAMS of oxygen are present in 5.76×1022 molecules of tetraphosphorus decaoxide ? _____grams of oxygen

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5. How many MOLECULES of disulfur decafluoride are present in 1.59 grams of this compound ? ______ molecules

6. How many GRAMS of disulfur decafluoride are present in 1.04×1023 molecules of this compound ? ______ grams.

Explanation / Answer

1) 1 mole of CO(28 g) contains 6.022 x 1023 atoms
     7.09 g CO contains (6.022x1023 * 7.09) / 28 = 1.524 x 1023 atoms

2) 6.022 x 1023 molecules of CO are present in 1 mole CO
    4.89 x 1022 molecules of CO are present in 0.0812 mole CO
    Grams of Oxygen present = 0.0812 x 16 g = 1.299 grams

3) 7.29 gms P4O10 = 7.29 g / 283.886 g/mol = 2.567 x 10-2 mol P4O10

Number of atoms present = 2.567 x 10-2 * 6.022 x 1023 = 15.45 x 1021 atoms

4) Number of moles of P4O10 = 5.76x1022 / 6.022x1023 = 9.56x 10-2 mol

Grams of Oxygen present = 160 * 9.56 x 10-2 = 15.3 grams ( 1 mole of P4O10 contains 16 gx10 = 160 g Oxygen)

** Answering only first four due to policy and time constaints, please post the questions seperately. Sorry to dissapoint you.

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