NaHCO 3 (CH 3 ) 3 C + BBr 3 (p K a = 25) CH 3 CH 2 Li CF 3 COONa NaH CH 3 ONa CH

Question

NaHCO3

(CH3)3C+

BBr3

(pKa = 25)

CH3CH2Li

CF3COONa

NaH

CH3ONa

CH3NHNa

Write the formula of the conjugate base of each acid: HBr, HNO3, and CH3CH2CH2OH.
Be sure to answer all parts.

HBr    

HNO3   

CH3CH2CH2OH    

Which compounds are Lewis acids? Select all that apply.
   N

C   

NaHCO3

  

(CH3)3C+

  

BBr3

Select all that apply.

Which of the following bases are strong enough to deprotonate CH3CH2CH2C

CH

(pKa = 25)

, so that equilibrium favors the products?   

CH3CH2Li

  

CF3COONa

  

NaH

  

CH3ONa

   NaCN   

CH3NHNa

Explanation / Answer

Solution :-

#1) When the acid dissociates then it gives off the hydronium ion and negatively charged conjugate base.

The conjugate acid base differ by 1 proton (H^+)

Following are the conjugate bases of the given acids

HBr ---- >   Br^-

HNO3 ---->   NO3^-

CH3CH2CH2OH --->   CH3CH2CH2O^-

#2) The compounds which are accepts the electron pair are considered as lewis acids.

Among the given list of compounds (CH3)3C^+ and BBr3 are lewis acids.

#3) alkyne is weakly acidic in nature therefore it requires strong base to deprotonates the alkyne .

CH3CH2Li and NaH are strong bases which can be used to deprotonate the alkyne.

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