NaCl, NaBr, NaI, Na2SO4, Na3PO4, Na2CO3 The following three solutions were analy
ID: 514372 • Letter: N
Question
NaCl, NaBr, NaI, Na2SO4, Na3PO4, Na2CO3
The following three solutions were analyzed according to the scheme used in this experiment. Which one, if any, of the ions tested, is present in each solution? If the data indicate that none of the six is present, write the word "None" as your answer. (a) Silver Nitrate Test. Yellow precipitate formed, which dissolved in dilute nitric acid. Barium Chloride Test. White precipitate formed, which dissolved in dilute hydrochloric acid. Organic solvent Test. The decane layer remained almost colorless after treatment with chlorine water. Anion present _____ (b) Silver Nitrate Test. Red precipitate formed, which dissolved in dilute nitric acid to give an orange solution. Barium Chloride Test. Yellow precipitate formed, which dissolved in dilute hydrochloric acid to give an orange solution. Organic solvent Test. The decane layer remained almost colorless after treatment with chlorine water. Anion present _____ (c) Silver Nitrate Test. Yellow precipitate formed, which did not dissolve in dilute acid. Barium Chloride Test. No precipitate formed. Organic solvent Test. The decane layer turned reddish-brown. Anion present _____Explanation / Answer
1a) The silver salt of the anion dissolves in dilute HNO3. The barium salt of the anion dissolves in dilute HCl. The anion doesn’t discolor the decane layer after treatment with chlorine water. The anion present is carbonate , CO32- and the salt is Na2CO3. The following equations are helpful.
Na2CO3 (aq) + 2 AgNO3 (aq) -------> Ag2CO3 (s, yellow) + 2 NaNO3
Ag2CO3 (s) + 2 HNO3 (aq) ------> 2 AgNO3 (aq) + CO2 (g) + H2O (l)
BaCl2 (aq) + Na2CO3 (aq) -----> BaCO3 (s, white) + 2 NaCl (aq)
BaCO3 (s) + 2 HCl (aq) -----> BaCl2 (aq) + CO2 (g) + H2O (l)
c) The silver salt is yellow in color which doesn’t dissolve in acid. The anion doesn’t react with barium chloride and forms a red colour with chlorine water in decane. The anion is iodide and the salt is NaI. The following reactions take place.
NaI (aq) + AgNO3 (aq) ------> AgI (s, yellow) + NaNO3
b) None of the anions match the desciption given; hence it must have been a different anion.
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