From the solubility experiment you will have concluded that biphenyl is soluble

Question

From the solubility experiment you will have concluded that biphenyl is soluble in hexane. On the following solute/solvent representation , state ALL of the IMF that need to be broken in BOT H the biphenyl solute and also in the solvent hexane. Draw a representation of the important IMF in the solid and solvent using the "dashed line" representation that we use in these packages . Do the same for the representation of the solution (right hand side of the equation below).

Characterize the energy cost associated with breaking the IMF in the solute and solvent as small or large?

Characterize the energy gain associated with making the IMF in the solute /solvent mixture as small or large?

Entropy always favors solvation (solution of a solid in a solvent) unless the overall energy requirement is large. Characterize the OVERALL energy requirement associated with making and breaking the IMF in the solute /solvent mixture as small or large?

Give a brief 1-sentence explanation for why biphenyl is soluble in hexane in terms of the various energiesassociated with the IMFs involved, and the entropy of the process.

I need the full answer please

Explanation / Answer

At first I would suggest you to type your question properly along with all information next time and avoid using short forms as different people uses different short forms for different words.

I think by IMF you mean Inter Moecular Forces and I am answering your question according to this only.

Biphenyl is soluble in hexane as both are nonpolar molecules and as we know like dissolves like.

Intermolecular forces that exist between solute molecules (biphenyl -biphenyl), solvent molecules (hexane-hexane) and solution (biphenyl-hexane) are weak vandenderwall forces.

As biphenyl is dissolved in hexane the forces between biphenyl molecues and hexane molecules has to be overcome and the new vanderwall forces between biphenyl and hexane molecules are established that is solute- solvent intractions that are weaker than the forces of soute-solute and solvent-solvent molecules and thus entropy also increases.

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