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Laboratory6 Spectroscopic Determination of an Equilibrium Constant DATE: NAME SE

ID: 712532 • Letter: L

Question

Laboratory6 Spectroscopic Determination of an Equilibrium Constant DATE: NAME SECTION: INSTRUCTOR In-Lab Guidelines (This is a guide to the information that you should be observing while in the laboratory. Record this information in the Laboratory Notebook. Turn in the duplicat period.) e pages of your observations to your Instructor before you leave the laboratory 2S Laboratory Temperature Concentration of Stock Fe(NO,), soln 0020 Concentration of stock KSCN soln. Trhal eKSCVHO Total Vol Fe(NO)KSCN H,o mL %T Observations: (anything you observed that may have affected your experiment, formation of a precipitate, spils, etc.) LABORATORY SPECTROSCOPIC RETERMDL

Explanation / Answer

Using = 4400 L/mol-cm

Path length, b = 1 cm

C = A / ( b)

A = 2 – log(%T)

We get below table:

Trial

% Transmittance

Absorption

[FeSCN]

1

7.2

1.14

0.00026

2

10.4

0.98

0.000223

3

16

0.80

0.000181

4

25.6

0.59

0.000134

Initial concentrations are obtained by using, M1 * V1 = M2 * V2

Trial

Total volume

Fe(NO3)3 volume, mL

KSCN volume, mL

Initial [Fe3+], M

Initial [SCN-], M

1

10

5

5

0.001

0.001

2

10

5

4

0.001

0.0008

3

10

5

3

0.001

0.0006

4

10

5

2

0.001

0.0004

Equilibrium concentrations:

[Fe3+]eq = [Fe3+]0 – [FeSCN]eq

[SCN-]eq = [SCN-]0 – [FeSCN]eq

Keq = [FeSCN]eq / ([Fe3+]eq [SCN-]eq)

Trial

Initial [Fe3+]

Initial [SCN-]

Eq. [FeSCN]

Eq. [Fe3+]

Eq. [SCN-]

Keq

Average Keq

1

0.001

0.001

0.00026

0.00074

0.00074

473.9

521.2

2

0.001

0.0008

0.000223

0.00078

0.00058

498.9

3

0.001

0.0006

0.000181

0.00082

0.00042

526.9

4

0.001

0.0004

0.000134

0.00087

0.00027

585.3

Possible errors in experiment:

a) Inaccurate preparation of initial solutions.

b) Improper readings given by instruments.

c) Temperature variations of the solution.

Trial

% Transmittance

Absorption

[FeSCN]

1

7.2

1.14

0.00026

2

10.4

0.98

0.000223

3

16

0.80

0.000181

4

25.6

0.59

0.000134