Laboratory Questions: 1- Part D.1 What is the fate of Zn2+ in the experiment? Ex

Question

Laboratory Questions:

1- Part D.1 What is the fate of Zn2+ in the experiment? Explain.

2- Part D.2 Instead of 6 M HNO3 being added to the solution, 6 M HCl is added (both are strong acids). How will this affect the test for the presence of copper (II) ion in the solution? Explain.

3- Part D.3 Instead of conc NH3 being added to the solution, 6 M NaOH is added (both are bases). How will this affect the test for the identifecation of copper (II) ion in the solution? Explain.

4- Part E.1 Instead of 6 M NH3 being added to the solution, 6 M NaOH is added (both are bases) before the addition of K2C2O4. What would be the appearance of the solution? Explain

Explanation / Answer

1) the fate of Zinc is that it will get oxidized to Zn+2. The Zn+2 will be absrobed by solution.

2) If we take HCl instead of HNO3 then the solution will turn green due to formation of complex between copper ion and chloride ion.

3) IF we use NaOH instead of NH3 then we will obtain a ppt of copper hydroxide instead of blue coloured complex of coppe with ammonia , [Cu(NH3)4]2+

So with NaOH we will get a ppt while with ammonia we will get blue coloured solution.

4) We will not observe any visible change as neither potassium nor oxalate reacts with ammonia or NaOH

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