For problems 11 and 12: Consider the following imaginary equilibrium: A2 (s) 2A(
ID: 711928 • Letter: F
Question
For problems 11 and 12: Consider the following imaginary equilibrium: A2 (s) 2A(g) 11) A is placed in a container. When equilibrium is reached, the pressure of A is 2 atm. What is the value of Kp? A) 0.25 B) 0.8 C) 2 D) 4 E) It depends on the mass of A 12) The reaction is exothermic (releases heat). How can the equilibrium be shifted to the right to produce more Ag? A) Add more A. B) Raise the temperature C) Increase the pressure by reducing the volume. D) Remove A from the system. E) Both answers A and D are correct.Explanation / Answer
11)
Kp = p(A)^2
= (2)^2
= 4
Answer: D
12)
A)
Adding solid or liquid doesn't affect equilibrium
So, No effect on equilibrium
B)
Increasing Temperature will shift the reaction in a direction which absorbs heat as per Le chatelier Principle
Forward reaction is exothermic in nature
hence, backward reaction will be favoured
So, Equilibrium moves to reactant side
C)
Decreasing volume will increase the pressure which in turn shift the reaction in a direction which have lesser gaseous molecules as per Le chatelier Principle
Here reactant has less gaseous molecule
So equilibrium will move to left
So, Equilibrium moves to reactant side
D)
Removing product will shift the reaction in the direction of product as per Le chatelier Principle
So, Equilibrium moves to product side
Answer: D
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