CHEM-1120-01L- General Chemistry II rse Content Materials ? Tools? Activities.,

Question

CHEM-1120-01L- General Chemistry II rse Content Materials ? Tools? Activities., User iz 4 Module 04- Equilibrium Limit: 0:45:00Time Left.0:15:50 Daniel Fox: Attempt1 Question 5 (1 point) B 9 questions saved What is the equilibrium constant for the reaction, N2H4 () + H2 (g) = 2 NH3 (g) given the reactions below? a B N2 (8) +2 H2(gN2H4)K1 24x 10-3 2 NH3 (g) N2 (g)+3 H2 (8) K2 2.0x10-3 2.9 x 10-3 2.1 x 105 5.1 x 102 end aved Response nsaved Response ·4.7×10-6 Question 1 Saved 1.2 MacBook Pro 2 3 4 5 6 8 0

Explanation / Answer

Given, N2(g) + 2H2(g) = N2H4(l) K1= 2.4*10^-3

2NH3(g) = N2(g) + 3H2(g) K2= 2.0*10^-3

Adding both reaction,

2NH3(g) = N2H4(l) + H2(g) K3 = 2.4*10^-3*2.0*10^-3 = 4.8*10^-6

Now, reverse the reaction,

N2H4(l) + H2(g) = 2NH3(g) .K = 1/K3 = 1/4.8*10^-6 = 2.083*10^5

= 2.1*10^5

Second option is correct.

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