Molarity and Dilution of Solutions 145 Using their densities, determine the conc

Question

Molarity and Dilution of Solutions 145 Using their densities, determine the concentrations of the following pure liquids. Hints: Find the mass for a given volume, and convert the mass to moles.) 5. a. water (use 1.00 g/ml. as the density of water) b. acetic acid, density 1.049 g/cm 6. A 25.00 mL. aliquot of concentrated hydrochloric acid (11.7 M) is added to 175.00 ml. of 3.25 M hydrochloric acid. a. Is this a dilution? Determine the number of moles of hydrochloric acid from the 175.00 mL of 3.25 M hydrochloric acid. b. Determine the number of moles of hydrochloric acid in the solution after the addition of the concentrated hydrochloric acid. Assume the volumes are additive. c. Determine the molarity of the solution after the addition of the concentrated hydrochloric acid. Assume the volumes are additive. d.

Explanation / Answer

5:. For water ,

Convert the given volume into mass , as mass = density (g/mL) × volume (mL) .

From mass ., No. Of moles = mass/molar mass of water = mass/18g/mol = no.of moles of water .

Similarly , for acetic acid ,

After calculating mass ,

No. Of moles of acetic acid = mass/ molar mass of acetic acid = mass/60g/mol .

If further molarity has to calculate ,

Then molarity = no. Of moles of substance/volume of solution in Litre .

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