OSMOSIS AND OSMOTIC PRESSURE 619 35. The concentration in gram per litre of a so

Question

OSMOSIS AND OSMOTIC PRESSURE 619 35. The concentration in gram per litre of a solution of cane sugar (mol mass - 342) is isotonie with a solution containing 3 gms of urea per litre. The concentration of cane sugar is (a)17.1 g lir (c) 3.42 g lt (b) 34.2 g lit () 1.71 g lir 36. The osmotic pressure of 10% solution of cane sugar at 69 C is (b) 0.821 atm (a) 16.42 atm (a) 0.0821 atm (c) 8.21 atm 37. Osmotic pressure is not determined by (a) Pfeffer's method (c) Abbe's refractometer (b) (d) Berkley and Hertley's method all of these 38. Which of the following is not correct? (a) in osmosis solvent molecules flow in one direction (b) in diffusion solute and solvent molecule flow in opposite direction (c) for osmosis a semipermeable membrane is required (d) for diffusion, a semipermeable membrane is required 39. The osmotic pressure of a solution of cane sugar (mol mass 342) at 69 °C is 8.21 atm. The concentration of the solution is (a) 1% (c) 596 (6) (d) 296 10% The volume of the solution containing one mole of solute that shows an osmotic pressure of I atm is (a) 22.4 litre (c) 0.224 litre 40. (b) 2.24 litre (d) 1.0 litre Which of the following types of compounds will have van't Hoff factor-1? (a) strong electrolytes (c) non-electrolytes 41. (b) weak electrolytes (d) none of these 42 For binary electrolytes of the type AB, the abnormal mol. mass is given by (a is the degree of dissociation) (b) M 1+? (c) Mnt 1+2a 1 +3a Which one of the following is not correct? (a) the equimolar solutions have same osmotic pressure at different temperatures (b) 43. the equimolar solutions have same osmotic pressure at same temperatures (e) the oumotic pressure is directly proportional to the number of moles of solutions d) the osmotie pressure is directly proportional to the relative lowering of vapour pressure

Explanation / Answer

Ans 35

For isotonic solution

Osmotic pressure of cane sugar solution = Osmotic pressure of urea solution

Concentration of cane sugar x R x T = Concentration of urea x R x T

At constant temperature

R is gas constant

Molar Concentration of cane sugar = molar Concentration of urea

Moles of cane sugar / volume of cane sugar = Moles of urea/ volume of urea

Mass of cane sugar / ( MW x volume) of cane sugar =Mass of urea / ( MW x volume) of urea

Mass of cane sugar / (342 x volume of cane sugar) = 3g / ( 60 x 1L)

Mass of cane sugar / volume of cane sugar = (3g x 342)/ ( 60 x 1L)

Mass of cane sugar / volume of cane sugar = 17.1 g/L

Concentration of cane sugar = 17.1 g/L

Option A is the correct answer

Ans 36

Basis - 100 g in 1 L of solution

Concentration of cane sugar = 100 g/L x 10/100 = 10 g/L

Molar concentration of cane sugar = (10 g/L) / (342g/mol)

= 0.0292 mol/L

Osmotic pressure = C x R x T

= 0.0292 mol/L x 0.0821 L-atm/mol-K x (69 + 273)K

= 0.821 atm

Option B is the correct answer

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