OSMOLARITY and milliOsmolarity 1 Calculate the osmolarity of a 0.15 M CaCl2 (aq)

Question

OSMOLARITY and milliOsmolarity 1 Calculate the osmolarity of a 0.15 M CaCl2 (aq) solution. Express this in milliosmolarity (mOSm). 0.45 OsM and 450 mOsM 2 Calculate the osmolarity of a 0.15 M glucose (CeH) (aq). Express this in milliosmolarity (mOSm). 0.15 OsM and 150 mOsM 3) You have 1.00 M solutions of the following. Arrange the following in order of increasing osmolarity potassium chloride osmolarity values: magnesium chloride sodium phosphate urea (CHN O) 4) Convert 10.0 % m/v CaC 2 (aq) to molarity and osmolarity. 0.901 M and 2.70 OsM

Explanation / Answer

To calculate osmolarity we need to consider VanHoff factor (i)

1)
CaCl2 ---> Ca2+ + 2Cl-
it breaks into 3 particle
so, i=3

osmolarity = i*[CaCl2]
= 3*0.15 OsM
= 0.45 OsM
= 450 mOsM

2)
This is covalent compound and hence doesn't dissociate or associate
so, i=1

osmolarity = 1*[glucose]
= 0.15 OsM
= 0.15 OsM
= 150 mOsM

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