ou a mc our 2) To cool your 250.0 mL of coffee at 90.0°C, you put a metal spoon

Question

ou a mc our 2) To cool your 250.0 mL of coffee at 90.0°C, you put a metal spoon in a glass of ice water to lower its temperature to 0.00°C, and then you put the spoon in the coffee. After thermal equilibrium has been reached, what is the [Tinal temperature of your coffee? Assume energy is exchanged only between the spoon and the coffee. The heat capacity of the metal spoon is 80.o JOC. Assume the specific heat and density of coffee are the same as that of water, 4.18 J/(g·°C) and 1.00 g/mL Some 0°c 2SomL . 1.Aen, tee tf

Explanation / Answer

Heat gained by spoon = Heat released by coffee

Cp x (T - 0) = mass x Cp x (90- T)

80 x T = 250 x 1 x 4.18 x (90 - T)

80 x T = 1045 x (90 - T)

80 x T = 94050 - 1045 T

1125 T = 94050

T = 83.6 °C

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.