ANSWER: The balanced equation is: Sn 2+ (aq) + Ba(s) ------------> Sn (s) + Ba 2

Question

ANSWER:

The balanced equation is:

Sn2+ (aq) + Ba(s) ------------> Sn (s) + Ba2+ (aq)

The Cell potential can be calculated by Nernst equation at 25oC

Ecell = Eocell - (0.059/ n) log [Ba2+ (aq)] / [Sn2+ (aq)]

n = No. of electrons involved in balanced equation = 2 in ths case

Eocell = EoR - EoL

EoR - = electrode potential of reduction half (Sn2+/Sn) and EoL = electrode potential of roxidation half (Ba2+/Ba)

Eocell = (-0.14) - (-2.91) = 2.77V

Using value of  Eocell in equation 1)

Ecell = 2.77 - (0.059 / 2) log (7.52 / 3.74)

Ecell = 2.77 - (0.059 / 2) X 0.301 = 2.76V

Explanation / Answer

Usi… A galvanic cell at a temperature of 25.0 is powered by the following redox reaction Sn2 (a)+ Ba(s)Sn)+Ba (aq) Suppose the cell is prepared with 3.74M Sn2 in one half-cell and 7.52M Ba in the other Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. -I

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