af a reaction between two species doubles when the concentration of the first re

Question

af a reaction between two species doubles when the concentration of the first reactant s doubled while that of the second is held constant. When the concentration of the frst reactant is held constant the rate increases with the square root of the concentration of the ather meactant. Determine the averall order of the reaction and explain how you got your answer For the mechanism A+ B C + B (k forward reaction, k-l reverse) 6. The steady state approximation should be used for 7. Using the steady state approximation, show rate= KIA] for the case when k2-

Explanation / Answer

5.

From the given data,

rate = k[A][B]1/2

So, overall order = 1 + ( 1 / 2 ) = 3/2 = 1.5

6.

For C only we apply steady state approximation.

7.

Rate = + d[P]/dt = k2[C] ------------- (1)

Applying steady approximation to [C]

k1[A][B] - k-1[C][B] - k2[C] = 0

[C] = k1[A][B] / (k-1[B] + k2]

From (1)

Rate = k2 * k1 [A][B] / (k-1[B] + k2)

If k2 <<< k-1, k1

Rate = k1 [A][B] / k-1[B]

Rate = (k1 / k-1) [A]

Rate = K[A]

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