. While playing pong, you can’t find a ping pong ball, so a friend suggests usin
ID: 695144 • Letter: #
Question
. While playing pong, you can’t find a ping pong ball, so a friend suggests using a golf ball. During the game, you throw the golf ball weighing 42.9 g at 25.0°C into a cup containing 300 g of water at 4.0°C. If the final temperature of the system is 11.0°C, what is the heat capacity of the golf ball in J/°C? Assume that the water has a heat capacity of 4.20 J/g°C, and that the heat capacity of the cup is negligible. (1) 14.7 J/°C (2) 180 J/°C (3) 630 J/°C (4) 206 J/°C (5) 8820 J/°C
The answer is 630 J/C. I just need an explanation.
Explanation / Answer
The energy balance
-warm golf ball = cold water
heat of golf ball = Cpball*(Tf-Tball)
heat of water = mwater*Cpwater*(Tf-Twater)
substitute
-Cpball*(Tf-Tball) = mwater*Cpwater*(Tf-Twater)
-Cpball(11-25) = 300*4.184*(11-4)
Cball = 300*4.184*(11-4)/(-(11-25)) = 627.6J/°C
roundin up to 2 sig fig --> 630 J/C°
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