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User Dashboard xUniversity of Kentucky d www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=4622576 Sapling Learning macmilan learming Destiny Young Jump to... Print Periodic Table Question 6 f 10 Available From: Due Date: Points Possible: Grade Category: Not Sct 12/8/201711:55 PM 10 Extra Credit Map General Chemistry 4th Edition University Science Books presented by Sapling Leaing At noon on a clear day, sunlight reaches the earth's surface at Madison, Wisconsin, with an average power of approximately 5.00 kJ m 2. If the sunlight consists of photons with an average wavelength of 510.0 nm, how many photons strike a 6.20 cm2 area per second? Policies Homework Number You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up You lose 5% of the points available to each photons s in your question for each i ncorrect attempt at that answer 10 1 100 O eTextbook Help With This Topic O Web Help & Videos Technical Support and Bug Reports Previous Give Up & View Solulian O Check Answer Next a Exit Hint 12:42 PM O Type here to search 12/4/2017

Explanation / Answer

A = 6.20 cm^2
= 0.000620 m^2

Energy hitting this area per seconds = 5.00 KJ/m^2 * 0.000620 m^2
= 5000 KJ/m^2 * 0.000620 m^2
= 3.100 J

Given:
lambda = 5.1*10^-7 m
1st calculate energy of 1 photon

Given:
lambda = 5.1*10^-7 m

use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(5.1*10^-7 m)
= 3.898*10^-19 J

number of photon = total energy/energy of 1 photon
n = 3.1/3.898*10^-19
= 7.95*10^18
Answer: 7.95*10^18

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