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User Dashboard xUniversity of Kentucky d www.saplinglearning.com/ibiscms/mod/ibi

ID: 693470 • Letter: U

Question

User Dashboard xUniversity of Kentucky d www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=4622576 Sapling Learning macmilan learming Destiny Young Jump to... Print Periodic Table Question 3 f 10 Available From: Due Date: Points Possible: Grade Category: Not Sct 12/8/201711:55 PM 10 Extra Credit Map sapling Learning What is the formula for copper(lI) phosphate? Capitalization and punctuation count! Policies Homework You can check your answers. You can view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up You lose 5% of the points available to each How many atoms of phosphorus are in 5.80 mol of copper(I) phosphate? in your question for each i ncorrect Number attempt at that answer 10 1 100 P atoms O eTextbook Help With This Topic O Web Help & Videos Technical Support and Bug Reports Previous Give Up & View Solulian O Check Answer Next a Exit Hint 12:39 PM O Type here to search 12/4/2017

Explanation / Answer

oxidation state of Cu is 2
oxidation state PO4 is 3
so, formula is
Cu3(PO4)2

molar mass of Cu3(PO4)2 = 380.6 g/mol
number of mole of Cu3(PO4)2 = (given mass)/(molar mass)
= 5.80/380.6
= 0.0152 mole

1 mol of Cu3(PO4)2 has 2 mol of P
0.0152 mol of Cu3(PO4)2 has (2*0.0152) mol of P
number of mole of P = 0.0304 mole

number of mole of P atom = (number of mole of P)*(6.022*10^23)
= 0.0304*6.022*10^23
= (1.83*10^22)

Answer : 1.83*10^22

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