I’ve actually had negative caloric content. How much energy, in each of the foll
ID: 692466 • Letter: I
Question
I’ve actually had negative caloric content. How much energy, in each of the following units, does your body lose from eating (and therefore melting) 57g of ice? Heat of fusion for water is 6.02 kJ/mol A. Express in joules B. Express in kilojoules C. Express in cal D. Express in Cal I’ve actually had negative caloric content. How much energy, in each of the following units, does your body lose from eating (and therefore melting) 57g of ice? Heat of fusion for water is 6.02 kJ/mol A. Express in joules B. Express in kilojoules C. Express in cal D. Express in Cal A. Express in joules B. Express in kilojoules C. Express in cal D. Express in CalExplanation / Answer
temperature of body = 37 C
now moles of water = mass/ molar mass of water , molar mass of water = 18
= 57/ 18 = 3.167 moles
total heat of fusion = 3.167 * 6.02 =19.06534 kj
now temperature rises from 0 to 37 C
total heat = mass * specific heat * change in temperature , specific heat = 4.186 , change in temperature = 37 88
57* 4.186 * 37= 8828.274 j
total heat required =19065.34 + 8828.274 =27893.614 j
1. in joules = 27893.614 j
2 . in kilojoules = 27.893614 Kj
3 . in cal = total energy in joule / 4.186 = 27893.614/ 4.186 = 6663.5484 cal
4 .in kcal = 6.66354 Cal
here in this problem i considered that the ice is melt from 0 C to 0 C and then reaches the body temperature of human being.
IF U SATISFY WITH THE SOLUTION PLEASE LIKE IT .................THNKXXXXXXX
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.