I’m having trouble figuring out how to use the first page in answering the quest

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I’m having trouble figuring out how to use the first page in answering the question CHM 232/EXPERIMENT F Lab Section 6) Date performed Record the following information during the laboratory period. Bucket number: Name lolia Laha Lab Partner Part 1: Saponification _1. Concentration ofHCl titrant 0.950 n Record the titration data for the saponification reaction below. Shaded boxes require no data. Show the units for each value given. Blank oil Butter Sample mass Final buret reading Initial buret reading Volume of HCl added 5. 60 15 60 8 80 Part 2: Trans fat content _1. A standard curve (Peak area versus % trans fat) from the standards (elaidic acid and soy oil) is displayed on the board. Write the equation of the regression line below. [1 pt :6.917x 6.74q 2. Report the value for the peak area that you obtained from the FTIR and calculate the % trans-fat content in the butter and in the margarine you analyzed in lab. Show your calculation below. [4 pts] . butter Parka margarine 1.31 peak area118 peak area 137:0 947616.469 -62-69976 t 0.7469 0.653 I]? %trans-fat %trans-fat 3. Record from the whiteboard, the average values of peak area for each sample, calculate the % trans fat in each and record your results in the table below [3 pts] Peak area (avg %trans fat butter 1.64 13 1,595 099 Par kau margarine caultr ek margarine 0.39? /13 pts 62

Explanation / Answer

number of moles of OH- = number of moles of H+= concentration × volume

so, 1 mole of HCL reacts with one mole of OH- so number of moles of HCL =number of moles of OH-

number of moles of H+= concentration × volume

so for Blank, number of moles of HCL = 0.250 * 15.60 = 3.9 moles =number of moles of OH- in blank

and for soy oil, number of moles of HCL = 0.250 * 9.20 = 2.3 moles =number of moles of OH-

for butter,  0.250 * 8.80= 2.2 moles  of OH-

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