HELP PLEASE! Can you please answer these questions with detailed steps. I am con

Question

HELP PLEASE! Can you please answer these questions with detailed steps. I am confused and really trying to understand this. Thanks!

1. Batteries were analyzed, the concentration of Li+ and Sn2+ were: [Sn2+] = 1.1 x 10-6 M and [Li+] = 5.0x 10-3. Calculate E for this cell is this battery dead? Explain.

2. The bath salt used was NaCl. If current flowed through the water, electrolysis of water occurred.

- For this give the half-reaction for the production of oxygen gas from the electrolysis of water.

- If the batteries supplied 13260 C, what volume of oxygen gas was made at 1 atm pressure and 25°C?

Explanation / Answer

1)

Lets find Eo 1st

from data table:

Eo(Li+/Li(s)) = -3.0401 V

Eo(Sn2+/Sn(s)) = -0.13 V

the electrode with the greater Eo value will be reduced and it will be cathode

here:

cathode is (Sn2+/Sn(s))

anode is (Li+/Li(s))

The chemical reaction taking place is

Sn2+(aq) + 2 Li(s) --> Sn(s) + 2 Li+(aq)

Eocell = Eocathode - Eoanode

= (-0.13) - (-3.0401)

= 2.9101 V

Number of electron being transferred in balanced reaction is 2

So, n = 2

we have below equation to be used:

E = Eo - (2.303*RT/nF) log {[Li+]^2/[Sn2+]^1}

Here:

2.303*R*T/F

= 2.303*8.314*298.0/96500

= 0.0591

So, above expression becomes:

E = Eo - (0.0591/n) log {[Li+]^2/[Sn2+]^1}

E = 2.91 - (0.0591/2) log (0.005^2/(1.1*10^-6))

E = 2.91-(4.01*10^-2)

E = 2.87 V

Answer: 2.87 V

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