Item 9 Part A An ideal gas at a pressure of 1.90 atm is contained in a bulb of u

Question

Item 9 Part A An ideal gas at a pressure of 1.90 atm is contained in a bulb of unknown volume. A stopcock is used to connect this bu volume of 0.900 L as shown here. When the stopcock is opened the gas expands into the empty bulb. (Figure 1) If the temperature is held constant during this process and the final pressure is 673 torr, what is the volume of the bulb that was originally filled with gas? lb with a previously evacuated bulb that has a Express your answer with the appropriate units v=10.420 L Submit My Answers Give Up Figure 1 of 1 Incorrect; Try Again; 5 attempts remaining Provide Feedback Continue

Explanation / Answer

P1V1 = 1.9*0.90 = 1.71 atm

P2V2 = 0

PV ratio is kept constant so

P1V1 + P2V2 = P3V3

P3V3 = 1.71

P = 673 torr = 0.8855 atm

0.8855 *V3 = 1.71

V3 = 1.71/0.8855 = 1.931 L

V2 = V3-V1 = 1.931-0.90 = 1.031L

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