Item 9 Part A An electron moves in the magnetic field B- 0.430 i T with a speed

Question

Item 9 Part A An electron moves in the magnetic field B- 0.430 i T with a speed of 1 .00 × 10' m/s in the directions shown in the fiqure. For each, what is magnetic force F on the electron? (Fiqure 1 Express vector F in the form off, I', where the x, y, and z components are separated by commas ? (Figure 1) 10, 0,1.98. 10 12 Submit My Answers Give Up Incorrect; Try Again; 8 attempts remaining Part B Express vector F in the form of F, F,, where the x, y, and z components are separated by commas ] Submit My Answers Give Up Figure 1 of! Continue 45

Explanation / Answer

Given,

Magnetic field, B = 0.430 i T

Velocity, V = 1 x 107 m/s

Here, we will use following relation,

Magnetic force, F= q x V x B

a) F = 1.6 x 10-19 x  1 x 107 x 0.430 k N

F = 6.88 x 10-13 N in the direction of k

Therefore, its component would be,

Fx = 0 N, Fy = 0 N, Fz = - 6.88 x 10-13 N

b) F = 1.6 x 10-19 x 1 x 107 x 0.430/sqrt(2) (j-k)

Fx = 0 N, Fy = - 4.86 x 10-13 N, Fz = - 4.86 x 10-13 N

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