Similar to the book just different values..? A solution contains a mixture of pe

Question

Similar to the book just different values..? A solution contains a mixture of pentane and hexane at roomtemperature. The solution has a vapor pressure of 261 torr.Pure pentane and hexane have vapor pressures of 425 torr and151 torr, respectively, at room temperature. What is the mole fraction of hexane? (Assumeideal behavior) Similar to the book just different values..? A solution contains a mixture of pentane and hexane at roomtemperature. The solution has a vapor pressure of 261 torr.Pure pentane and hexane have vapor pressures of 425 torr and151 torr, respectively, at room temperature. What is the mole fraction of hexane? (Assumeideal behavior) What is the mole fraction of hexane? (Assumeideal behavior)

Explanation / Answer

let x = mol fraction of hexane 1- x = mol fraction of pentane Vapor pressure = mol frac hexane*pure vapor pressure hexane + molfrac pentane*pure vapor pressure pentane 261 torr = x*(151) + ( 1- x)*425 = -274*x + 425 x = (261 - 425)/(-274) = 0.598540146 => x =0.599   (so about 60% of the moles are hexane)

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