Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questi

Question

Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 3.29 x 10-5 M NaCI(aq) solution. At some temperature, the silver ion concentration, [Ag+, was found to be 4.30 x 10-6 M. (a) What is the concentration of chloride ions, [CI-, in the resulting solution? (No Response) M (b) what is the molar solubility of silver chloride. Aga, in 3.29 × 10-5 M Naci? No Response) M (c) The solubility of Agci(s) in pure water is 1.26 x 10-5 M. Did the solubility increase or decrease in 3.29 x 10-5 M Naci solution? No Response (d) What is the solubility product constant, Ksp, for silver chloride, Agci? sp=

Explanation / Answer

a)

NACl + Ag+ = AgCl + Na+

[Cl-] left = 3.29*10^-5 - 4.3*10^-6 = 0.0000286 M

b)

Molar solubility can be assumed to be

Ksp = [Ag+][Cl-]

assume [Cl-] is in excess so

(1.8*10^-10) = (S) * (0.0000286 )

S = (1.8*10^-10) / 0.0000286

S = 0.00000629 M of AgCl in such solution

c)

Ksp = [Ag+][Cl-]

since [Cl-] is already present, the shift goes towards AgCl(s) formation, so Ag+ decreases

d)

Ksp = [Ag+][Cl-]

[Ag+] = [Cl-] = 1.26*10^-5

Ksp = (1.26*10^-5)(1.26*10^-5) = 1.587*10^-10

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