Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questi

Question

Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 3.91 times 10^-5 M NaCI(aq) solution. At some temperature, the silver ion concentration, [Ag^+], was found to be 3.74 times 10^-6 M. (a) What is the concentration of chloride ions, [CI^-], in the resulting solution? 3.91e-5 (b) What is the molar solubility of silver chloride, AgCI, in 3.91 times 10^5 M NaCI? 1.53e-9 M (c) The solubility of AgCI(s) in pure water is 1.26 times 10^-5 M. Did the solubility increase or decrease in 3.91 times 10^-5 M NaCI solution? (d) What is the solubility product constant, K_sp, for silver chloride, AgCI? K_sp =

Explanation / Answer

If we break the AgCl according to their ions then:

AgCl = Ag+ + Cl-

there is 1:1 between Ag+ and Cl-

Now, considered we prepare 1L of AgCL solution,

We know: [Ag+] = 3.74 * 10^-6 M

Hence: [Cl-] = 3.74 * 10^-6 M (because ratio is 1:1)

(a): Now NaCl can be break like this NaCl = Na+ + Cl- (here also ratio is 1:1)

So, Total Cl- =  3.74 * 10^-6 + 3.91 * 10^-5

= 4.284 * 10^-5 M

Answer (a) = 4.284 * 10^-5 M

(b) Since, we know that in AgCl solution ratio between Ag+ and Cl- is 1:1.

So, 1 mole of AgCL = 1 mole of Ag+ and 1 mole of Cl-

So, molar solubility of AgCl = 1* [Ag+]

= 1* 3.74 *10-6

So, Answer (b) = 3.74*10-6 M

(c): solubility will decrease, because AgCl having Cl- ions, and NaCl also Cl- ions, so due to its common ion effect solubility of AgCl will decrease.

(d): Solubility product constant Ksp is known as solubility product constant or solubility product. Since the solubility of a salt usually varies widely with temperature, the numerical value of Ksp for a salt changes with temperature.

Generally, if the sparingly soluble salt, Ax By is in equilibrium with saturated solution of its ions, then
Ax By = x Ay+ + y Bx-

Where Ay+ and Bx- denote the positive and negative ions respectively and x and y represent the number of these ions in the formula of the electrolyte.

The solubility product expression is:
Ksp = [Ay+] x [Bx-] y

so, In our case: Ksp = [Ag+]^1 * [Cl-]^1

= 3.74 * 10^-6 *3.74 * 10^-6

Answer (d) = 13.99 * 10^-12

Hope this solution will helps you.

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