How much dry solute would you take to prepare each of thefollowing solutions fro

Question

How much dry solute would you take to prepare each of thefollowing solutions from the dry solute and the solvent?

115 g of 0.100 m NaNO3 = ? g NaNo3

115 g of 1.4 % NaNO3 solution by mass = ? g NaNo3

How much solvent would you take to prepare the solution in115 g of 0.100 m NaNO3 ? = g H2O

How much solvent would you take to prepare the solution in115 g of 1.4 % NaNO3 solution by mass ? = g H2O

Explanation / Answer

0.1 mol NaNO3 / 1 kg solvent For every 1 kg water, also 0.1 mol NaNO3 => 0.1 mol NaNO3 *(85g/mol) = 8.5 grams 1008.5 grams of solution for every 8.5 grams NaNO3 115 g solution *(8.5 gram NaNO3/ 1008.5 grams solution) = 0.970grams NaNO3 =================== 115 g *(0.014) = 1.61 grams ================== Recall that part 1) resulted in 0.970 grams NaNO3 115 - 0.970 = 114.03 ~ 114 grams water ================== 115 - 1.61 = 113 grams water

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