PLease show how to Balance the following reaction, you may need to add: C2CL4 +

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C2Cl4 = >    C2H4  +    Cl- balance Cl's C2Cl4 = >    C2H4  +    4Cl- C on left goes from having +2 charge (2 * +2 countearacts the four-1 of Cl in C2Cl4) to having -2 on the right (H's have +1, so four+1 is counteracted by two -2's.). So each C changes by an oxidationstate of 4. There are 2 C's on each side, so add 8 electronsto the right C2Cl4 + 8 e- = > C2H4   + 4Cl- Balance H's by adding 4H+ on the left C2Cl4 + 8 e- + 4H+ = > C2H4   +4Cl- Now balance Fe => Fe2+ Add two electrons on the right Fe = > Fe2+ + 2e- Take a linear combination of the two bolded equations, such thatelectrons are eliminated C2Cl4 + 8 e- + 4H+ = > C2H4   +4Cl-                         4(Fe = > Fe2+ + 2e-) ----------------------------------------------- C2Cl4 + 4Fe + 4H+ = >C2H4   + 4Cl- +4 Fe2+ Equation is balanced

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