CAN SOMEONE PLEASE HELP ME? 1.How many milliliters of 0.0711 M Ca(OH) 2 would be

Question

CAN SOMEONE PLEASE HELP ME? 1.How many milliliters of 0.0711 M Ca(OH)2would be required to exactly neutralize 181 mL of0.163 M HCl?

2.How many milliliters of 0.974 M HCl would berequired to exactly neutralize 240 mL of 0.517 M NaOH?

CAN SOMEONE PLEASE HELP ME? 1.How many milliliters of 0.0711 M Ca(OH)2would be required to exactly neutralize 181 mL of0.163 M HCl?

2.How many milliliters of 0.974 M HCl would berequired to exactly neutralize 240 mL of 0.517 M NaOH?

Explanation / Answer

For this type of problem it is necessary to know that when you'reneutralizing the moles of acid=moles of base. Now, let's do thefirst one. 1) You know you have 181 mL of 0.163M HCl. Figure out the number ofmoles you have by rearranging M=n/V, to be n=MV. (note: Makesure to convert those mL to L by dividing by 1000). The trickything with this problem is that you have to write down yourreaction to get the correct number of moles. 2HCl + Ca(OH)2 ---> 2H2O +CaCl2. 2n=0.163M(0.181L)=0.01475 moles. To neutralize you would need thesame amount of moles of Ca(OH)2. To get the volumerearrange the formula once more to get. V=n/M=(0.02595moles)/0.0711M= 0.20745L=207.45 mL 2) This one is relatively easier because you have 1:1 ratios. Figure out the number of moles of NaOH. 0.517M(.24L)=.12408moles. Need the same amount of moles of acid. So, the volume=.12408moles/.974M=.12739mL=127.39mL If it helps to clarify remember that (M1V1/n1)=(M2V2/n2) Hope this helps!

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