The electrochemical cell described by the balancedchemical reaction has a standa

Question

The electrochemical cell described by the balancedchemical reaction has a standard cell potential of -0.04 V.Calculate the equilibrium constant (Kc) for the reactionat 25 oC. Round your answer to 3 significantfigures.

Cd(s) + Fe2+(aq) Cd2+(aq) + Fe(s)


St. Red. Pot. (V) Cd2+/Cd -0.40 Fe2+/Fe -0.44 Constants 0 °C = 273.15 K R = 8.314 J/(K x mol) Faraday's Constant 96485 C/mol The electrochemical cell described by the balancedchemical reaction has a standard cell potential of -0.04 V.Calculate the equilibrium constant (Kc) for the reactionat 25 oC. Round your answer to 3 significantfigures.

Cd(s) + Fe2+(aq) Cd2+(aq) + Fe(s)


St. Red. Pot. (V) Cd2+/Cd -0.40 Fe2+/Fe -0.44 Constants 0 °C = 273.15 K R = 8.314 J/(K x mol) Faraday's Constant 96485 C/mol

Explanation / Answer

We know that
          Eocell = Ecathode -Eanode                    = EFe+2/Fe - ECd/Cd+2                    = -0.44 - (-0.40)                    = -0.04 V Since    -nFEocell = -RTlnK               ln K = nFEocell / RT                       = 2*96500*(-0.04) /8.314*298                       = -3.115 Therfore      K =e-3.115                          =0.04433                          =0.04433

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