How many moles of sodium hydroxide have been added if 22.11 mL of.128 M solution

Question

How many moles of sodium hydroxide have been added if 22.11 mL of.128 M solution are added to titration?

If the sodium hydroxide in the problem above is added to 50.00 mLof .118M Hydrochloric acid, how many mmoles of hydrochloric acidremain? How many moles of sodium hydroxide have been added if 22.11 mL of.128 M solution are added to titration?

If the sodium hydroxide in the problem above is added to 50.00 mLof .118M Hydrochloric acid, how many mmoles of hydrochloric acidremain?

Explanation / Answer

NaOH + HCl -> NaCl + H2O n(HCl) = cv = 0.128 x 0.02211 = 0.002830mol n(NaOH) = n(HCl) = 0.002830mol Second question n(HCl) = cv = 0.118 x 0.05 = 0.0059mol n(HCl) remaining = 0.0059 - 0.00283 = 0.00307mol = 3.07mmol Hope this helps!

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