If 1 mol of N_2 and 1 mol H_2 are mixed what is the max # ofmols of NH_3 that co

Question

If 1 mol of N_2 and 1 mol H_2 are mixed what is the max # ofmols of NH_3 that could be produced? N_2 + 3H_2 ---> 2NH_3 Answer:   2/3 moles How do you get this? If 1 mol of N_2 and 1 mol H_2 are mixed what is the max # ofmols of NH_3 that could be produced? N_2 + 3H_2 ---> 2NH_3 Answer:   2/3 moles How do you get this?

Explanation / Answer

N2 + 3H2 ->2NH3 First, you need to find which reactant is the limiting reagent Stoichiometry ratio = n(N2)/n(H2) = 1/3 =0.33 Actual ratio = n(N2)/n(H2) = 1/1 = 1 Actual Ratio > Stoichiometry ratio So, H2 is the limiting reagent. So, the maximum number of moles of NH3 that can beproduced = 2/3 x n(H2 ) = 2/3 x 1 = 2/3 moles Hope this helps!

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