C3H6 + CO + H2 ? C4H8? In an existing process, 180 kgmol/h of C,H, (P) is mixed

Question

C3H6 + CO + H2 ? C4H8? In an existing process, 180 kgmol/h of C,H, (P) is mixed with 420 kgmol/h of a mixture containing 50% CO (C) and 50% H, (H) and with a recycle stream containing propylene and then fed to a reactor. 30% of the propylene fed to the reactor is consumed. The reactor effluent is sent to a separator. The desired product butanal (B) is removed in one stream, unreacted CO and H, are removed in a second stream, and unreacted P is recovered and recycled 6 Mixer Reactor SeparatorC, H P, C, C, H2 How many material balance equations are there for the process?

Explanation / Answer

Total material balance at mixure =03 ( 3 components P,C,H)

Total material balance at reactor=04( 4 components P,C,H,B)

Total material balance at Seperator =04 (4 components( P,C,H,B)

Total material balance Equation= 03+04+04 =11

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