C3H6 + CO + H2 C4H80 In an existing process, 180 kgmol/h of C,H, (P) is mixed wi

Question

C3H6 + CO + H2 C4H80 In an existing process, 180 kgmol/h of C,H, (P) is mixed with 420 kgmol/h of a mixture containing 50% CO (C) and 50% H, (H) and with a recycle stream containing propylene and then fed to a reactor, 30% of the propylene fed to the reactor is consumed. The reactor effluent is sent to a separator. The desired product butanal (B) is removed in one stream, unreacted CO and H, are removed in a second stream, and unreacted P is recovered and recycled 3 Mixer Reactor SeparatorC, H P,C, HI ?, ?, H, B C,H 2 Which of the following equations correctly express the specifed flows (in kgmol/h)? Select all that are correct (Hint: there are 2 correct choices).

Explanation / Answer

Cons = consumed

Gen = generation

Balance B around separator

B4 = B7

Balance C around reactor

C3 = C(cons) + C4

Balance C around separator

C4 = C6

C2 = C(cons) + C6

C2 - C(cons) = C6

Balance B around separator

B4 = B7

B(gen) = B7

P1 = P(cons)

P3 = 180 kmol

P4 = 180*0.70 = 126 kmol

P4 = P5 = 126 kmol

B4 = B(gen) = 180*0.3 = 54 kmol = P(cons)......... Eq1

B4 = B7 = 54 kmol...... Eq2

P1 + P5 = P3

P1 = 180 - 126 = 54 kmol........ Eq3

From eq3 and eq1

P1 = P(cons) is correct

From Eq 3 and eq2

P1 = B7

From the options

P1 = 180 incorrect

C2 = C3 correct

C2 = 420 incorrect

B7 = 180 incorrect

C2 = H2 correct

C2 + H2 = 420 correct

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